aoc/year2017/day02.rs
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//! # Corruption Checksum
//!
//! Part two is `O(n²)` complexity but at least we can reduce by a factor of two by sorting
//! each line first, allowing us to only compare each number against those that are greater.
//! As a minor benefit this makes part one faster too.
use crate::util::parse::*;
type Input = Vec<Vec<u32>>;
pub fn parse(input: &str) -> Input {
input
.lines()
.map(|line| {
let mut values: Vec<_> = line.iter_unsigned().collect();
values.sort_unstable();
values
})
.collect()
}
pub fn part1(input: &Input) -> u32 {
input.iter().map(|values| values[values.len() - 1] - values[0]).sum()
}
pub fn part2(input: &Input) -> u32 {
input
.iter()
.map(|values| {
for i in 0..values.len() {
for j in i + 1..values.len() {
if values[j] % values[i] == 0 {
return values[j] / values[i];
}
}
}
unreachable!()
})
.sum()
}